BRADENTON, Florida – The stage is set for the 2019 Concacaf Boys’ Under-15 Championship in which 16 teams in Division 1 compete for regional superiority at the IMG Academy in Bradenton, Florida from August 4-11.
Reigning champions Mexico will be out to defend its title beginning in Group A where it will face 2017 CBU15 third-place side Panama, Trinidad and Tobago and Curacao.
2017 finalists United States headlines Group B which also features Haiti, Guatemala and Suriname.
Group C will see Canada, El Salvador and Guadeloupe go up against invitees Slovenia.
Rounding out Division 1 is Group D in which Costa Rica, Jamaica and Barbados will take on another invitee, Portugal.
Division 1 group winner and runner up from A, B, C and D will advance to compete for the championship trophy.
- Division 1
- Group A – Mexico, Panama, Trinidad & Tobago, Curacao
- Group B – USA, Haiti, Guatemala, Suriname
- Group C – Canada, El Salvador, Slovenia, Guadeloupe
- Group D – Costa Rica, Jamaica, Portugal, Barbados
